Linear Programming Problem with Example
Essay by Weshura Malaka • November 17, 2017 • Essay • 1,189 Words (5 Pages) • 1,287 Views
- Defining The Problem Of Beyond Era (Pvt) Ltd
The beyond era pvt ltd is company they produce and selling water bottle to market. Last month they imported new 2 water bottle product machine from china.
- Water bottles filing machine
- Water bottles packing machine
Those days very hot and have high demand for water bottle. They produce two size wetter bottles.
- 500 ML bottle
- 1000 ML bottle
The marketing team has concluded that the company could sell as much of either product per day as could be produced by these machine. However, those tow machine hours are limiting factors. According to machine manufacturing company those tow machine only can work per day as follows
- Filing Machine 12 H
- Packing machine 10 H
So beyond era pvt ltd management thinking about how many no of water bottle pack both tow size should be produced to maximize their profit .this is product mix type linear programming problem. so we have to select best product mix using linear programmer model .
- Identified Some Date To Solved This Problem
- How many bottles in one pack? 100 PCS
- Number of time of produce time use in each machine to produce each 2 bottle pack? it’s as follows
MACHINE | TIME REQUIRED TO PRODUCE 100 PCS BOTTLE PACK | AVAILABLE HOURS PER DAY | |
500 ML BOTTLE PACK | 1000 ML BOTTLE PACK | ||
FILING | 2M | 4M | 12*60 = 720M |
PACKING | 3M | 2M | 10*60 = 600M |
- How much each bottle pack profit?
- 500 ml 100 Pcs pack Rs 3000/=
- 1000 ml 100 Pcs pack Rs 5000/=
According to above data beyond era pvt ltd management want to know that what is the best product mix to produce to reach the maximum profit .
- Mathematical Formulation
Beyond era management is looking best product mix of both products to maximize their profit. So, we identified this is product mix linear programming problem . using graphical and simplex method we will advice to management to select their best production mix to maximize their profit .
Data we have collect as follows
MACHINE | TIME REQUIRED TO PRODUCE 100PCS BOTTLE PACK | AVAILABLE HOURS | |
500 ML BOTTLES PACK(X) | 1000 ML BOTTLES PACK(Y) | PER DAY | |
FILING | 2M | 4M | 12*60 = 720M |
PACKING | 3M | 2M | 10*60 = 600M |
PROFIT PER UNIT | RS 3000 | RS 5000 |
|
- The objective is to maximize profit.
- The constraints are
- The hours of filing machine time use cannot exceed 12 hours per day.
- The hours of packing machine time use cannot exceed 10 hours per day
- The decision variables representing the actual decision we will make are
- X = number of 500 ml bottles pack to be produced per day
- Y = number of 1000 ml bottles pack to be produced per day.
So we can develop mathematical function as follows
- Profit maximization = Rs3000X + Rs5000Y
- Filing machine time using = 2X + 4Y < 720
- Packing machine time using = 3X + 2Y < 600
- Both of these constraints restrict production capacity and affect to profit
- The number of production X and Y greater than or equal to 0 so X,Y > 0
- Develop A Solution
3.1) Graphical solution
To use above data we solved linear programmed using graphical method as follows.
We can short collect data like this
X | Y | |||
Z | 3000 | 5000 |
|
|
FILING | 2 | 4 | < | 720 |
PACKING | 3 | 2 | < | 600 |
- The fist step in solving the problem is to identify a set of region of feasible solution
- To do this we plot each constraint equation on a graph.
- When 1000ml bottles production is 0 500ml bottles production by fully using filling machine as follows
2x + 4y <= 720
2x + 4(0) <= 720
2x <= 720
X = 720/2
X = 360
- Similarly no 500ml bottle
2x + 4y <= 720
2(0) + 4Y <= 720
4Y <= 720
Y = 720/4
Y = 180
- After solving above tow equations we can make flowing table for filing machine
FILING | |
X | Y |
360 | 0 |
0 | 180 |
- Same as we can make table for packing machine as follows
3x + 2y <= 600
3x + 2(0) <= 600
3x <= 600
...
...